Compiler Errors 

private namespace rss;
private namespace xml;
    
public function ErrorExamples() {
  	use namespace rss;
   	use namespace xml;
	trace(hello());
}
    
rss function hello():String {
      	return "hola";
    }
    
    xml function hello():String {
        return "foo";
    }

Correct an ambiguous reference by making the reference specific. The following example uses the form namespace::function to specify which namespace to use:

public function ErrorExamples() {
    
    trace(rss::hello());
    trace(xml::hello());
}

public override function foo():void{};

The error can also occur if the class being referenced is not defined in a namespace that is in use or is not defined as public:

public class Foo{}

If you are using Flex™ Builder™ 2 and the class is in a library, make sure to set the class path for the project.

class D { function xx() { return 22; } }
var d:D = new D();
var x = new d.xx(); // error, method cannot be used as constructor
function yy() { this.a = 22; }
var z = new yy(); // no error, global functions can be used as constructors.

public function set gamma(g:Number):Number;

The following is valid:

public function set gamma(g:Number):void;

In the following example, line 3 generates an error because there is no setter function defined for xx:

class D { function get xx() { return 22; } }
var d:D = new D();
d.xx = 44; // error, property is read-only

public int z;// should be 'public var z:int;'

trace "hello"

switch(x)
{
trace(2);
case 0:  trace(0); 
break
}

var sum:int = 1 + 2 + ;

If the error says "Expecting left parenthesis before _," you may have omitted a parenthesis from a conditional expression, as shown in the following example, which is intentionally incorrect:

var fact:int = 1 * 2 * 3;
if fact > 2 {
	var bigger:Boolean = true;
}

var x = (5 > 2) ? 
trace(x)

File a.as contains the following, which attempts to include the file b.as:

import foo.bar.baz;
include "b.as"
trace(2);

File b.as contains the following, which attempts to include the file a.as:

include "a.as"

class a extends b { }
class b extends a { }

Perhaps you are using a supertype where a subtype is expected. For example:

class A {}
var a:A = new A(); 
class B extends A { function f() }
var b : B = a // error

The last statement generates an error because it attempts to assign an object of type A to a variable of type B.

Similarly, the following defines the foo() function, which takes a parameter of type B. The statement foo(a); generates an error because it attempts to use a parameter of type A:

function foo(x:B) { }
foo(a);

Also, the following statement generates an error because the returned value for foo2() must be type B:

function foo2():B { return new A(); }

var i:int = 44;
var str:String = i.assortment;

huh = 55;

class A { static function goo(x:int,y:int) 
{ return(x+y); } }

The following statement would generate an error because it provides three arguments:

A.goo(1,2,3);

The following code example correctly casts the variable x as the same type:

function test()
{
	var x:int = 3;
	for(var x:int = 33; x < 55; x++)
	trace(x);
	for(var x:int = 11; x < 33; x++)
	trace(x)
}

The following code example generates an error because the type casting in the variable declaration and the for loops are different:

function test()
{
	var x:String = "The answer is";
	for(var x:int = 33; x < 55; x++) // error
	trace(x);
	for(var x:unit = 11; x < 33; x++) // error
	trace(x)
}

interface A {  public function f();  };
class C implements A,A {
public function f() { trace("f"); }
}

The correct implementing statement should be class C implements A {.

function topLevel() { trace("top"); }
topLevel = function() { trace("replacement works in ~");} // error

function f(x):int
{
if (x)
    	return 2;
else
    	return 3;
} // no error

However, the function g(x) below generates the error because the switch statement does not always return a value.

function g(x:int):int
{
switch(x)
{
      	case 1: return 1;
      	case 2: return 2:
}
// return 2;//uncomment to remove the error
}

This checking is enabled only when the function declares a return type other than void.

p.huh = 55;